-10-8x-x^2 eching

$$- 10 - 8 x - x ^ { 2 }$$

Omil

$$-\left(x-\left(-\sqrt{6}-4\right)\right)\left(x-\left(\sqrt{6}-4\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-x^{2}-8x-10=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-8\right)±\sqrt{\left(-8\right)^{2}-4\left(-1\right)\left(-10\right)}}{2\left(-1\right)}$$

-8 kvadratini chiqarish.

$$x=\frac{-\left(-8\right)±\sqrt{64-4\left(-1\right)\left(-10\right)}}{2\left(-1\right)}$$

-4 ni -1 marotabaga ko'paytirish.

$$x=\frac{-\left(-8\right)±\sqrt{64+4\left(-10\right)}}{2\left(-1\right)}$$

4 ni -10 marotabaga ko'paytirish.

$$x=\frac{-\left(-8\right)±\sqrt{64-40}}{2\left(-1\right)}$$

64 ni -40 ga qo'shish.

$$x=\frac{-\left(-8\right)±\sqrt{24}}{2\left(-1\right)}$$

24 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-8\right)±2\sqrt{6}}{2\left(-1\right)}$$

-8 ning teskarisi 8 ga teng.

$$x=\frac{8±2\sqrt{6}}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{8±2\sqrt{6}}{-2}$$

x=\frac{8±2\sqrt{6}}{-2} tenglamasini yeching, bunda ± musbat. 8 ni 2\sqrt{6} ga qo'shish.

$$x=\frac{2\sqrt{6}+8}{-2}$$

8+2\sqrt{6} ni -2 ga bo'lish.

$$x=-\left(\sqrt{6}+4\right)$$

x=\frac{8±2\sqrt{6}}{-2} tenglamasini yeching, bunda ± manfiy. 8 dan 2\sqrt{6} ni ayirish.

$$x=\frac{8-2\sqrt{6}}{-2}$$

8-2\sqrt{6} ni -2 ga bo'lish.

$$x=\sqrt{6}-4$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -\left(4+\sqrt{6}\right) ga va x_{2} uchun -4+\sqrt{6} ga bo‘ling.

$$-x^{2}-8x-10=-\left(x-\left(-\left(\sqrt{6}+4\right)\right)\right)\left(x-\left(\sqrt{6}-4\right)\right)$$

Baholash

$$-x^{2}-8x-10$$