-1x^2+2=0 eching

$$- 1 x ^ { 2 } + 2 = 0$$

x uchun yechish

$$x=\sqrt{2}\approx 1,414213562$$

$$x=-\sqrt{2}\approx -1,414213562$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 2 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-x^{2}=-2$$

Ikki tarafini -1 ga bo‘ling.

$$x^{2}=\frac{-2}{-1}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-2}{-1} kasrini 2 ga soddalashtirish mumkin.

$$x^{2}=2$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{2} x=-\sqrt{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$-x^{2}+2=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -1 ni a, 0 ni b va 2 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 2}}{2\left(-1\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-1\right)\times 2}}{2\left(-1\right)}$$

-4 ni -1 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{4\times 2}}{2\left(-1\right)}$$

4 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{8}}{2\left(-1\right)}$$

8 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{2}}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{0±2\sqrt{2}}{-2}$$

x=\frac{0±2\sqrt{2}}{-2} tenglamasini yeching, bunda ± musbat.

$$x=-\sqrt{2}$$

x=\frac{0±2\sqrt{2}}{-2} tenglamasini yeching, bunda ± manfiy.

$$x=\sqrt{2}$$

Tenglama yechildi.

$$x=-\sqrt{2} x=\sqrt{2}$$