-1-5x^2=-321 eching

$$- 1 - 5 x ^ { 2 } = - 321$$

x uchun yechish

$$x=8$$

$$x=-8$$

Kvadrat ildizini topish bo'yicha qadamlar

1 ni ikki tarafga qo’shing.

$$-5x^{2}=-321+1$$

-320 olish uchun -321 va 1'ni qo'shing.

$$-5x^{2}=-320$$

Ikki tarafini -5 ga bo‘ling.

$$x^{2}=\frac{-320}{-5}$$

64 ni olish uchun -320 ni -5 ga bo‘ling.

$$x^{2}=64$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=8 x=-8$$

Kvadrat tenglamalaridan foydalanish qoidalari

321 ni ikki tarafga qo’shing.

$$-1-5x^{2}+321=0$$

320 olish uchun -1 va 321'ni qo'shing.

$$320-5x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$-5x^{2}+320=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -5 ni a, 0 ni b va 320 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-5\right)\times 320}}{2\left(-5\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-5\right)\times 320}}{2\left(-5\right)}$$

-4 ni -5 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{20\times 320}}{2\left(-5\right)}$$

20 ni 320 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{6400}}{2\left(-5\right)}$$

6400 ning kvadrat ildizini chiqarish.

$$x=\frac{0±80}{2\left(-5\right)}$$

2 ni -5 marotabaga ko'paytirish.

$$x=\frac{0±80}{-10}$$

x=\frac{0±80}{-10} tenglamasini yeching, bunda ± musbat. 80 ni -10 ga bo'lish.

$$x=-8$$

x=\frac{0±80}{-10} tenglamasini yeching, bunda ± manfiy. -80 ni -10 ga bo'lish.

$$x=8$$

Tenglama yechildi.

$$x=-8 x=8$$