-1=3x^2-4(x+2)+x eching

$$- 1 = 3 x ^ { 2 } - 4 ( x + 2 ) + x$$

x uchun yechish

$$x=\frac{\sqrt{93}}{6}+\frac{1}{2}\approx 2,107275127$$

$$x=-\frac{\sqrt{93}}{6}+\frac{1}{2}\approx -1,107275127$$

Kvadrat tenglamalaridan foydalanish qoidalari

-4 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-1=3x^{2}-4x-8+x$$

-3x ni olish uchun -4x va x ni birlashtirish.

$$-1=3x^{2}-3x-8$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$3x^{2}-3x-8=-1$$

1 ni ikki tarafga qo’shing.

$$3x^{2}-3x-8+1=0$$

-7 olish uchun -8 va 1'ni qo'shing.

$$3x^{2}-3x-7=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 3 ni a, -3 ni b va -7 ni c bilan almashtiring.

$$x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\times 3\left(-7\right)}}{2\times 3}$$

-3 kvadratini chiqarish.

$$x=\frac{-\left(-3\right)±\sqrt{9-4\times 3\left(-7\right)}}{2\times 3}$$

-4 ni 3 marotabaga ko'paytirish.

$$x=\frac{-\left(-3\right)±\sqrt{9-12\left(-7\right)}}{2\times 3}$$

-12 ni -7 marotabaga ko'paytirish.

$$x=\frac{-\left(-3\right)±\sqrt{9+84}}{2\times 3}$$

9 ni 84 ga qo'shish.

$$x=\frac{-\left(-3\right)±\sqrt{93}}{2\times 3}$$

-3 ning teskarisi 3 ga teng.

$$x=\frac{3±\sqrt{93}}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$x=\frac{3±\sqrt{93}}{6}$$

x=\frac{3±\sqrt{93}}{6} tenglamasini yeching, bunda ± musbat. 3 ni \sqrt{93} ga qo'shish.

$$x=\frac{\sqrt{93}+3}{6}$$

3+\sqrt{93} ni 6 ga bo'lish.

$$x=\frac{\sqrt{93}}{6}+\frac{1}{2}$$

x=\frac{3±\sqrt{93}}{6} tenglamasini yeching, bunda ± manfiy. 3 dan \sqrt{93} ni ayirish.

$$x=\frac{3-\sqrt{93}}{6}$$

3-\sqrt{93} ni 6 ga bo'lish.

$$x=-\frac{\sqrt{93}}{6}+\frac{1}{2}$$

Tenglama yechildi.

$$x=\frac{\sqrt{93}}{6}+\frac{1}{2} x=-\frac{\sqrt{93}}{6}+\frac{1}{2}$$

Kvadratni yakunlash bo'yicha qadamlar

-4 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-1=3x^{2}-4x-8+x$$

-3x ni olish uchun -4x va x ni birlashtirish.

$$-1=3x^{2}-3x-8$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$3x^{2}-3x-8=-1$$

8 ni ikki tarafga qo’shing.

$$3x^{2}-3x=-1+8$$

7 olish uchun -1 va 8'ni qo'shing.

$$3x^{2}-3x=7$$

Ikki tarafini 3 ga bo‘ling.

$$\frac{3x^{2}-3x}{3}=\frac{7}{3}$$

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$x^{2}+\left(-\frac{3}{3}\right)x=\frac{7}{3}$$

-3 ni 3 ga bo'lish.

$$x^{2}-x=\frac{7}{3}$$

-1 ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{1}{2} olish uchun. Keyin, -\frac{1}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=\frac{7}{3}+\left(-\frac{1}{2}\right)^{2}$$

Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{1}{2} kvadratini chiqarish.

$$x^{2}-x+\frac{1}{4}=\frac{7}{3}+\frac{1}{4}$$

Umumiy maxrajni topib va hisoblovchini qo'shish orqali \frac{7}{3} ni \frac{1}{4} ga qo'shing. So'ngra agar imkoni bo'lsa kasrni eng kam shartga qisqartiring.

$$x^{2}-x+\frac{1}{4}=\frac{31}{12}$$

x^{2}-x+\frac{1}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-\frac{1}{2}\right)^{2}=\frac{31}{12}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{31}{12}}$$

Qisqartirish.

$$x-\frac{1}{2}=\frac{\sqrt{93}}{6} x-\frac{1}{2}=-\frac{\sqrt{93}}{6}$$

\frac{1}{2} ni tenglamaning ikkala tarafiga qo'shish.

$$x=\frac{\sqrt{93}}{6}+\frac{1}{2} x=-\frac{\sqrt{93}}{6}+\frac{1}{2}$$