-(2+2x^2)+(1/5x+5/4x^2+4/3)-(-2/3-frac{3}{4}x^2+frac{1}{5}x) eching

$$- ( 2 + 2 x ^ { 2 } ) + ( \frac { 1 } { 5 } x + \frac { 5 } { 4 } x ^ { 2 } + \frac { 4 } { 3 } ) - ( - \frac { 2 } { 3 } - \frac { 3 } { 4 } x ^ { 2 } + \frac { 1 } { 5 } x )$$

Baholash

$$0$$

Yechim qadamlari

2+2x^{2} teskarisini topish uchun har birining teskarisini toping.

$$-2-2x^{2}+\frac{1}{5}x+\frac{5}{4}x^{2}+\frac{4}{3}-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

-\frac{3}{4}x^{2} ni olish uchun -2x^{2} va \frac{5}{4}x^{2} ni birlashtirish.

$$-2-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{4}{3}-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

-\frac{2}{3} olish uchun -2 va \frac{4}{3}'ni qo'shing.

$$-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x-\left(-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x\right)$$

-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x teskarisini topish uchun har birining teskarisini toping.

$$-\frac{2}{3}-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{2}{3}+\frac{3}{4}x^{2}-\frac{1}{5}x$$

0 olish uchun -\frac{2}{3} va \frac{2}{3}'ni qo'shing.

$$-\frac{3}{4}x^{2}+\frac{1}{5}x+\frac{3}{4}x^{2}-\frac{1}{5}x$$

0 ni olish uchun -\frac{3}{4}x^{2} va \frac{3}{4}x^{2} ni birlashtirish.

$$\frac{1}{5}x-\frac{1}{5}x$$

0 ni olish uchun \frac{1}{5}x va -\frac{1}{5}x ni birlashtirish.

$$0$$

Omil

$$0$$

Yechim qadamlari

\frac{1}{60} omili.

$$\frac{-120\left(1+x^{2}\right)+12x+75x^{2}+80-\left(-40-45x^{2}+12x\right)}{60}$$

Qisqartirish.

$$0$$