-x^2+25x+15 eching

$$- { x }^{ 2 } +25x+15$$

Omil

$$-\left(x-\frac{25-\sqrt{685}}{2}\right)\left(x-\frac{\sqrt{685}+25}{2}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-x^{2}+25x+15=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-25±\sqrt{25^{2}-4\left(-1\right)\times 15}}{2\left(-1\right)}$$

25 kvadratini chiqarish.

$$x=\frac{-25±\sqrt{625-4\left(-1\right)\times 15}}{2\left(-1\right)}$$

-4 ni -1 marotabaga ko'paytirish.

$$x=\frac{-25±\sqrt{625+4\times 15}}{2\left(-1\right)}$$

4 ni 15 marotabaga ko'paytirish.

$$x=\frac{-25±\sqrt{625+60}}{2\left(-1\right)}$$

625 ni 60 ga qo'shish.

$$x=\frac{-25±\sqrt{685}}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{-25±\sqrt{685}}{-2}$$

x=\frac{-25±\sqrt{685}}{-2} tenglamasini yeching, bunda ± musbat. -25 ni \sqrt{685} ga qo'shish.

$$x=\frac{\sqrt{685}-25}{-2}$$

-25+\sqrt{685} ni -2 ga bo'lish.

$$x=\frac{25-\sqrt{685}}{2}$$

x=\frac{-25±\sqrt{685}}{-2} tenglamasini yeching, bunda ± manfiy. -25 dan \sqrt{685} ni ayirish.

$$x=\frac{-\sqrt{685}-25}{-2}$$

-25-\sqrt{685} ni -2 ga bo'lish.

$$x=\frac{\sqrt{685}+25}{2}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{25-\sqrt{685}}{2} ga va x_{2} uchun \frac{25+\sqrt{685}}{2} ga bo‘ling.

$$-x^{2}+25x+15=-\left(x-\frac{25-\sqrt{685}}{2}\right)\left(x-\frac{\sqrt{685}+25}{2}\right)$$

Baholash

$$15+25x-x^{2}$$