x uchun yechish
x=-\frac{2}{7}\approx -0,285714286
Grafik
Viktorina
Linear Equation
5xshash muammolar:
- \frac{ 6 }{ 10 } x+ \frac{ 2 }{ 5 } = \frac{ x-1 }{ 3 } +1
Baham ko'rish
Klipbordga nusxa olish
30\left(-\frac{6}{10}\right)x+12=10\left(x-1\right)+30
Tenglamaning ikkala tarafini 30 ga, 10,5,3 ning eng kichik karralisiga ko‘paytiring.
30\left(-\frac{3}{5}\right)x+12=10\left(x-1\right)+30
\frac{6}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{30\left(-3\right)}{5}x+12=10\left(x-1\right)+30
30\left(-\frac{3}{5}\right) ni yagona kasrga aylantiring.
\frac{-90}{5}x+12=10\left(x-1\right)+30
-90 hosil qilish uchun 30 va -3 ni ko'paytirish.
-18x+12=10\left(x-1\right)+30
-18 ni olish uchun -90 ni 5 ga bo‘ling.
-18x+12=10x-10+30
10 ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
-18x+12=10x+20
20 olish uchun -10 va 30'ni qo'shing.
-18x+12-10x=20
Ikkala tarafdan 10x ni ayirish.
-28x+12=20
-28x ni olish uchun -18x va -10x ni birlashtirish.
-28x=20-12
Ikkala tarafdan 12 ni ayirish.
-28x=8
8 olish uchun 20 dan 12 ni ayirish.
x=\frac{8}{-28}
Ikki tarafini -28 ga bo‘ling.
x=-\frac{2}{7}
\frac{8}{-28} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
Misollar
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Matritsa
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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Differensatsiya
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Oʻngga
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Chegaralar
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