-3/1+2=-6/2v-4+1 eching

$$- \frac{ 3 }{ 1+2 } = - \frac{ 6 }{ 2v-4 } +1$$

v uchun yechish

$$v = \frac{7}{2} = 3\frac{1}{2} = 3,5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

v qiymati 2 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 2\left(v-2\right) ga ko'paytirish.

$$-\left(\frac{2}{3}v-\frac{4}{3}\right)\times 3=-6+2\left(v-2\right)$$

\frac{2}{3}v-\frac{4}{3} ga 3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-\left(2v-4\right)=-6+2\left(v-2\right)$$

2v-4 teskarisini topish uchun har birining teskarisini toping.

$$-2v+4=-6+2\left(v-2\right)$$

2 ga v-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2v+4=-6+2v-4$$

-10 olish uchun -6 dan 4 ni ayirish.

$$-2v+4=-10+2v$$

Ikkala tarafdan 2v ni ayirish.

$$-2v+4-2v=-10$$

-4v ni olish uchun -2v va -2v ni birlashtirish.

$$-4v+4=-10$$

Ikkala tarafdan 4 ni ayirish.

$$-4v=-10-4$$

-14 olish uchun -10 dan 4 ni ayirish.

$$-4v=-14$$

Ikki tarafini -4 ga bo‘ling.

$$v=\frac{-14}{-4}$$

\frac{-14}{-4} ulushini -2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$v=\frac{7}{2}$$