x uchun yechish
x=-8
x=0
Grafik
Baham ko'rish
Klipbordga nusxa olish
x\left(-\frac{1}{2}x-4\right)=0
x omili.
x=0 x=-8
Tenglamani yechish uchun x=0 va -\frac{x}{2}-4=0 ni yeching.
-\frac{1}{2}x^{2}-4x=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}}}{2\left(-\frac{1}{2}\right)}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -\frac{1}{2} ni a, -4 ni b va 0 ni c bilan almashtiring.
x=\frac{-\left(-4\right)±4}{2\left(-\frac{1}{2}\right)}
\left(-4\right)^{2} ning kvadrat ildizini chiqarish.
x=\frac{4±4}{2\left(-\frac{1}{2}\right)}
-4 ning teskarisi 4 ga teng.
x=\frac{4±4}{-1}
2 ni -\frac{1}{2} marotabaga ko'paytirish.
x=\frac{8}{-1}
x=\frac{4±4}{-1} tenglamasini yeching, bunda ± musbat. 4 ni 4 ga qo'shish.
x=-8
8 ni -1 ga bo'lish.
x=\frac{0}{-1}
x=\frac{4±4}{-1} tenglamasini yeching, bunda ± manfiy. 4 dan 4 ni ayirish.
x=0
0 ni -1 ga bo'lish.
x=-8 x=0
Tenglama yechildi.
-\frac{1}{2}x^{2}-4x=0
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
\frac{-\frac{1}{2}x^{2}-4x}{-\frac{1}{2}}=\frac{0}{-\frac{1}{2}}
Ikkala tarafini -2 ga ko‘paytiring.
x^{2}+\left(-\frac{4}{-\frac{1}{2}}\right)x=\frac{0}{-\frac{1}{2}}
-\frac{1}{2} ga bo'lish -\frac{1}{2} ga ko'paytirishni bekor qiladi.
x^{2}+8x=\frac{0}{-\frac{1}{2}}
-4 ni -\frac{1}{2} ga bo'lish -4 ga k'paytirish -\frac{1}{2} ga qaytarish.
x^{2}+8x=0
0 ni -\frac{1}{2} ga bo'lish 0 ga k'paytirish -\frac{1}{2} ga qaytarish.
x^{2}+8x+4^{2}=4^{2}
8 ni bo‘lish, x shartining koeffitsienti, 2 ga 4 olish uchun. Keyin, 4 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}+8x+16=16
4 kvadratini chiqarish.
\left(x+4\right)^{2}=16
x^{2}+8x+16 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x+4\right)^{2}}=\sqrt{16}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x+4=4 x+4=-4
Qisqartirish.
x=0 x=-8
Tenglamaning ikkala tarafidan 4 ni ayirish.
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