-1/3(9x-6y-3)= eching

$$- \frac { 1 } { 3 } ( 9 x - 6 y - 3 ) =$$

Baholash

$$1+2y-3x$$

Yechim qadamlari

-\frac{1}{3} ga 9x-6y-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-\frac{1}{3}\times 9x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

-\frac{1}{3}\times 9 ni yagona kasrga aylantiring.

$$\frac{-9}{3}x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

-3 ni olish uchun -9 ni 3 ga bo‘ling.

$$-3x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

-\frac{1}{3}\left(-6\right) ni yagona kasrga aylantiring.

$$-3x+\frac{-\left(-6\right)}{3}y-\frac{1}{3}\left(-3\right)$$

6 hosil qilish uchun -1 va -6 ni ko'paytirish.

$$-3x+\frac{6}{3}y-\frac{1}{3}\left(-3\right)$$

2 ni olish uchun 6 ni 3 ga bo‘ling.

$$-3x+2y-\frac{1}{3}\left(-3\right)$$

-\frac{1}{3}\left(-3\right) ni yagona kasrga aylantiring.

$$-3x+2y+\frac{-\left(-3\right)}{3}$$

3 hosil qilish uchun -1 va -3 ni ko'paytirish.

$$-3x+2y+\frac{3}{3}$$

1 ni olish uchun 3 ni 3 ga bo‘ling.

$$-3x+2y+1$$

Kengaytirish

$$1+2y-3x$$

Yechim qadamlari

-\frac{1}{3} ga 9x-6y-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-\frac{1}{3}\times 9x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

-\frac{1}{3}\times 9 ni yagona kasrga aylantiring.

$$\frac{-9}{3}x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

-3 ni olish uchun -9 ni 3 ga bo‘ling.

$$-3x-\frac{1}{3}\left(-6\right)y-\frac{1}{3}\left(-3\right)$$

-\frac{1}{3}\left(-6\right) ni yagona kasrga aylantiring.

$$-3x+\frac{-\left(-6\right)}{3}y-\frac{1}{3}\left(-3\right)$$

6 hosil qilish uchun -1 va -6 ni ko'paytirish.

$$-3x+\frac{6}{3}y-\frac{1}{3}\left(-3\right)$$

2 ni olish uchun 6 ni 3 ga bo‘ling.

$$-3x+2y-\frac{1}{3}\left(-3\right)$$

-\frac{1}{3}\left(-3\right) ni yagona kasrga aylantiring.

$$-3x+2y+\frac{-\left(-3\right)}{3}$$

3 hosil qilish uchun -1 va -3 ni ko'paytirish.

$$-3x+2y+\frac{3}{3}$$

1 ni olish uchun 3 ni 3 ga bo‘ling.

$$-3x+2y+1$$