-1/2(x+8)^2+18=10 eching

$$- \frac { 1 } { 2 } ( x + 8 ) ^ { 2 } + 18 = 10$$

x uchun yechish

$$x=-4$$

$$x=-12$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafidan 18 ni ayirish.

$$-\frac{1}{2}\left(x+8\right)^{2}+18-18=10-18$$

O‘zidan 18 ayirilsa 0 qoladi.

$$-\frac{1}{2}\left(x+8\right)^{2}=10-18$$

10 dan 18 ni ayirish.

$$-\frac{1}{2}\left(x+8\right)^{2}=-8$$

Ikkala tarafini -2 ga ko‘paytiring.

$$\frac{-\frac{1}{2}\left(x+8\right)^{2}}{-\frac{1}{2}}=-\frac{8}{-\frac{1}{2}}$$

-\frac{1}{2} ga bo'lish -\frac{1}{2} ga ko'paytirishni bekor qiladi.

$$\left(x+8\right)^{2}=-\frac{8}{-\frac{1}{2}}$$

-8 ni -\frac{1}{2} ga bo'lish -8 ga k'paytirish -\frac{1}{2} ga qaytarish.

$$\left(x+8\right)^{2}=16$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x+8=4 x+8=-4$$

Tenglamaning ikkala tarafidan 8 ni ayirish.

$$x+8-8=4-8 x+8-8=-4-8$$

O‘zidan 8 ayirilsa 0 qoladi.

$$x=4-8 x=-4-8$$

4 dan 8 ni ayirish.

$$x=-4$$

-4 dan 8 ni ayirish.

$$x=-12$$

Tenglama yechildi.

$$x=-4 x=-12$$