-1/2(2x-10y-3)=-1x+10y eching

$$- \frac { 1 } { 2 } ( 2 x - 10 y - 3 ) = - 1 x + 10 y$$

y uchun yechish

$$y = \frac{3}{10} = 0,3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-\frac{1}{2} ga 2x-10y-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-x+5y+\frac{3}{2}=-x+10y$$

Ikkala tarafdan 10y ni ayirish.

$$-x+5y+\frac{3}{2}-10y=-x$$

-5y ni olish uchun 5y va -10y ni birlashtirish.

$$-x-5y+\frac{3}{2}=-x$$

x ni ikki tarafga qo’shing.

$$-5y+\frac{3}{2}=-x+x$$

0 ni olish uchun -x va x ni birlashtirish.

$$-5y+\frac{3}{2}=0$$

Ikkala tarafdan \frac{3}{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-5y=-\frac{3}{2}$$

Ikki tarafini -5 ga bo‘ling.

$$y=\frac{-\frac{3}{2}}{-5}$$

\frac{-\frac{3}{2}}{-5} ni yagona kasrga aylantiring.

$$y=\frac{-3}{2\left(-5\right)}$$

-10 hosil qilish uchun 2 va -5 ni ko'paytirish.

$$y=\frac{-3}{-10}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-3}{-10} kasrini \frac{3}{10} ga soddalashtirish mumkin.

$$y=\frac{3}{10}$$

x uchun yechish (complex solution)

$$x\in \mathrm{C}$$

$$y = \frac{3}{10} = 0,3$$

x uchun yechish

$$x\in \mathrm{R}$$

$$y = \frac{3}{10} = 0,3$$