(y+2)(y+2)=16x eching

$$(y+2)(y+2)=16x$$

x uchun yechish

$$x=\frac{\left(y+2\right)^{2}}{16}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(y+2\right)^{2} hosil qilish uchun y+2 va y+2 ni ko'paytirish.

$$\left(y+2\right)^{2}=16x$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(y+2\right)^{2} kengaytirilishi uchun ishlating.

$$y^{2}+4y+4=16x$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$16x=y^{2}+4y+4$$

Ikki tarafini 16 ga bo‘ling.

$$\frac{16x}{16}=\frac{\left(y+2\right)^{2}}{16}$$

16 ga bo'lish 16 ga ko'paytirishni bekor qiladi.

$$x=\frac{\left(y+2\right)^{2}}{16}$$

y uchun yechish (complex solution)

$$y=-4\sqrt{x}-2$$

$$y=4\sqrt{x}-2$$

y uchun yechish

$$y=-4\sqrt{x}-2$$

$$y=4\sqrt{x}-2\text{, }x\geq 0$$