(x-2)(x+2)-(x-1)(x-3) eching

$$(x-2)(x+2)-(x-1)(x-3)$$

Baholash

$$4x-7$$

Yechim qadamlari

Hisoblang: \left(x-2\right)\left(x+2\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-2^{2}-\left(x-1\right)\left(x-3\right)$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$x^{2}-4-\left(x-1\right)\left(x-3\right)$$

x-1 ifodaning har bir elementini x-3 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$x^{2}-4-\left(x^{2}-3x-x+3\right)$$

-4x ni olish uchun -3x va -x ni birlashtirish.

$$x^{2}-4-\left(x^{2}-4x+3\right)$$

x^{2}-4x+3 teskarisini topish uchun har birining teskarisini toping.

$$x^{2}-4-x^{2}-\left(-4x\right)-3$$

-4x ning teskarisi 4x ga teng.

$$x^{2}-4-x^{2}+4x-3$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$-4+4x-3$$

-7 olish uchun -4 dan 3 ni ayirish.

$$-7+4x$$

Kengaytirish

$$4x-7$$

Yechim qadamlari

Hisoblang: \left(x-2\right)\left(x+2\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-2^{2}-\left(x-1\right)\left(x-3\right)$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$x^{2}-4-\left(x-1\right)\left(x-3\right)$$

x-1 ifodaning har bir elementini x-3 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$x^{2}-4-\left(x^{2}-3x-x+3\right)$$

-4x ni olish uchun -3x va -x ni birlashtirish.

$$x^{2}-4-\left(x^{2}-4x+3\right)$$

x^{2}-4x+3 teskarisini topish uchun har birining teskarisini toping.

$$x^{2}-4-x^{2}-\left(-4x\right)-3$$

-4x ning teskarisi 4x ga teng.

$$x^{2}-4-x^{2}+4x-3$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$-4+4x-3$$

-7 olish uchun -4 dan 3 ni ayirish.

$$-7+4x$$