(x+10)*(y-5)=300 eching

$$(x+10) \times (y-5)=300$$

x uchun yechish

$$x=-\frac{10\left(y-35\right)}{y-5}$$

$$y\neq 5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x+10 ga y-5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$xy-5x+10y-50=300$$

Ikkala tarafdan 10y ni ayirish.

$$xy-5x-50=300-10y$$

50 ni ikki tarafga qo’shing.

$$xy-5x=300-10y+50$$

350 olish uchun 300 va 50'ni qo'shing.

$$xy-5x=350-10y$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(y-5\right)x=350-10y$$

Ikki tarafini y-5 ga bo‘ling.

$$\frac{\left(y-5\right)x}{y-5}=\frac{350-10y}{y-5}$$

y-5 ga bo'lish y-5 ga ko'paytirishni bekor qiladi.

$$x=\frac{350-10y}{y-5}$$

350-10y ni y-5 ga bo'lish.

$$x=\frac{10\left(35-y\right)}{y-5}$$

y uchun yechish

$$y=\frac{5\left(x+70\right)}{x+10}$$

$$x\neq -10$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x+10 ga y-5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$xy-5x+10y-50=300$$

5x ni ikki tarafga qo’shing.

$$xy+10y-50=300+5x$$

50 ni ikki tarafga qo’shing.

$$xy+10y=300+5x+50$$

350 olish uchun 300 va 50'ni qo'shing.

$$xy+10y=350+5x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x+10\right)y=350+5x$$

Tenglama standart shaklda.

$$\left(x+10\right)y=5x+350$$

Ikki tarafini x+10 ga bo‘ling.

$$\frac{\left(x+10\right)y}{x+10}=\frac{5x+350}{x+10}$$

x+10 ga bo'lish x+10 ga ko'paytirishni bekor qiladi.

$$y=\frac{5x+350}{x+10}$$

350+5x ni x+10 ga bo'lish.

$$y=\frac{5\left(x+70\right)}{x+10}$$