(8x^2+1)=2 eching

$$(8 { x }^{ 2 } +1)=2$$

x uchun yechish

$$x=\frac{\sqrt{2}}{4}\approx 0,353553391$$

$$x=-\frac{\sqrt{2}}{4}\approx -0,353553391$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 1 ni ayirish.

$$8x^{2}=2-1$$

1 olish uchun 2 dan 1 ni ayirish.

$$8x^{2}=1$$

Ikki tarafini 8 ga bo‘ling.

$$x^{2}=\frac{1}{8}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\frac{\sqrt{2}}{4} x=-\frac{\sqrt{2}}{4}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 2 ni ayirish.

$$8x^{2}+1-2=0$$

-1 olish uchun 1 dan 2 ni ayirish.

$$8x^{2}-1=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 8 ni a, 0 ni b va -1 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 8\left(-1\right)}}{2\times 8}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 8\left(-1\right)}}{2\times 8}$$

-4 ni 8 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-32\left(-1\right)}}{2\times 8}$$

-32 ni -1 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{32}}{2\times 8}$$

32 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{2}}{2\times 8}$$

2 ni 8 marotabaga ko'paytirish.

$$x=\frac{0±4\sqrt{2}}{16}$$

x=\frac{0±4\sqrt{2}}{16} tenglamasini yeching, bunda ± musbat.

$$x=\frac{\sqrt{2}}{4}$$

x=\frac{0±4\sqrt{2}}{16} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{\sqrt{2}}{4}$$

Tenglama yechildi.

$$x=\frac{\sqrt{2}}{4} x=-\frac{\sqrt{2}}{4}$$