(2y+1)(y-1)=(y+5)(2y-5) eching

$$(2y+1)(y-1)=(y+5)(2y-5)$$

y uchun yechish

$$y=4$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2y+1 ga y-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2y^{2}-y-1=\left(y+5\right)\left(2y-5\right)$$

y+5 ga 2y-5 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2y^{2}-y-1=2y^{2}+5y-25$$

Ikkala tarafdan 2y^{2} ni ayirish.

$$2y^{2}-y-1-2y^{2}=5y-25$$

0 ni olish uchun 2y^{2} va -2y^{2} ni birlashtirish.

$$-y-1=5y-25$$

Ikkala tarafdan 5y ni ayirish.

$$-y-1-5y=-25$$

-6y ni olish uchun -y va -5y ni birlashtirish.

$$-6y-1=-25$$

1 ni ikki tarafga qo’shing.

$$-6y=-25+1$$

-24 olish uchun -25 va 1'ni qo'shing.

$$-6y=-24$$

Ikki tarafini -6 ga bo‘ling.

$$y=\frac{-24}{-6}$$

4 ni olish uchun -24 ni -6 ga bo‘ling.

$$y=4$$