(2(x+10)+3)div3*25=4x+05 eching

$$(2(x+10)+3) \div 3 \times 25=4x+05$$

x uchun yechish

$$x = -\frac{575}{38} = -15\frac{5}{38} \approx -15,131578947$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 3 ga ko'paytirish.

$$\left(2\left(x+10\right)+3\right)\times 25=12x+0\times 5$$

2 ga x+10 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(2x+20+3\right)\times 25=12x+0\times 5$$

23 olish uchun 20 va 3'ni qo'shing.

$$\left(2x+23\right)\times 25=12x+0\times 5$$

2x+23 ga 25 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$50x+575=12x+0\times 5$$

0 hosil qilish uchun 0 va 5 ni ko'paytirish.

$$50x+575=12x+0$$

Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$50x+575=12x$$

Ikkala tarafdan 12x ni ayirish.

$$50x+575-12x=0$$

38x ni olish uchun 50x va -12x ni birlashtirish.

$$38x+575=0$$

Ikkala tarafdan 575 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$38x=-575$$

Ikki tarafini 38 ga bo‘ling.

$$x=\frac{-575}{38}$$

\frac{-575}{38} kasri manfiy belgini olib tashlash bilan -\frac{575}{38} sifatida qayta yozilishi mumkin.

$$x=-\frac{575}{38}$$