(x-y)(400+5y)=4250 eching

$$( x - y ) ( 400 + 5 y ) = 4250$$

x uchun yechish

$$x=\frac{y^{2}+80y+850}{y+80}$$

$$y\neq -80$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x-y ga 400+5y ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$400x+5xy-400y-5y^{2}=4250$$

400y ni ikki tarafga qo’shing.

$$400x+5xy-5y^{2}=4250+400y$$

5y^{2} ni ikki tarafga qo’shing.

$$400x+5xy=4250+400y+5y^{2}$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(400+5y\right)x=4250+400y+5y^{2}$$

Tenglama standart shaklda.

$$\left(5y+400\right)x=5y^{2}+400y+4250$$

Ikki tarafini 400+5y ga bo‘ling.

$$\frac{\left(5y+400\right)x}{5y+400}=\frac{5y^{2}+400y+4250}{5y+400}$$

400+5y ga bo'lish 400+5y ga ko'paytirishni bekor qiladi.

$$x=\frac{5y^{2}+400y+4250}{5y+400}$$

4250+400y+5y^{2} ni 400+5y ga bo'lish.

$$x=\frac{y^{2}+80y+850}{y+80}$$

y uchun yechish (complex solution)

$$y=\frac{-\sqrt{x^{2}+160x+3000}+x-80}{2}$$

$$y=\frac{\sqrt{x^{2}+160x+3000}+x-80}{2}$$

y uchun yechish

$$y=\frac{-\sqrt{x^{2}+160x+3000}+x-80}{2}$$

$$y=\frac{\sqrt{x^{2}+160x+3000}+x-80}{2}\text{, }x\geq 10\sqrt{34}-80\text{ or }x\leq -10\sqrt{34}-80$$