(x-8)^2-x(x+6)=-2 eching

$$( x - 8 ) ^ { 2 } - x ( x + 6 ) = - 2$$

x uchun yechish

$$x=3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-8\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}-16x+64-x\left(x+6\right)=-2$$

x ga x+6 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{2}-16x+64-\left(x^{2}+6x\right)=-2$$

x^{2}+6x teskarisini topish uchun har birining teskarisini toping.

$$x^{2}-16x+64-x^{2}-6x=-2$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$-16x+64-6x=-2$$

-22x ni olish uchun -16x va -6x ni birlashtirish.

$$-22x+64=-2$$

Ikkala tarafdan 64 ni ayirish.

$$-22x=-2-64$$

-66 olish uchun -2 dan 64 ni ayirish.

$$-22x=-66$$

Ikki tarafini -22 ga bo‘ling.

$$x=\frac{-66}{-22}$$

3 ni olish uchun -66 ni -22 ga bo‘ling.

$$x=3$$