(x-6)^2+4=1 eching

$$( x - 6 ) ^ { 2 } + 4 = 1$$

x uchun yechish (complex solution)

$$x=-\sqrt{3}i+6\approx 6-1,732050808i$$

$$x=6+\sqrt{3}i\approx 6+1,732050808i$$

Kvadrat ildizini topish bo'yicha qadamlar

O‘zidan 4 ayirilsa 0 qoladi.

$$\left(x-6\right)^{2}=1-4$$

1 dan 4 ni ayirish.

$$\left(x-6\right)^{2}=-3$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x-6=\sqrt{3}i x-6=-\sqrt{3}i$$

6 ni tenglamaning ikkala tarafiga qo'shish.

$$x-6-\left(-6\right)=\sqrt{3}i-\left(-6\right) x-6-\left(-6\right)=-\sqrt{3}i-\left(-6\right)$$

O‘zidan -6 ayirilsa 0 qoladi.

$$x=\sqrt{3}i-\left(-6\right) x=-\sqrt{3}i-\left(-6\right)$$

i\sqrt{3} dan -6 ni ayirish.

$$x=6+\sqrt{3}i$$

-i\sqrt{3} dan -6 ni ayirish.

$$x=-\sqrt{3}i+6$$

Tenglama yechildi.

$$x=6+\sqrt{3}i x=-\sqrt{3}i+6$$