(x-3)(4x+2)=4x^2+3 eching

$$( x - 3 ) ( 4 x + 2 ) = 4 x ^ { 2 } + 3$$

x uchun yechish

$$x=-\frac{9}{10}=-0,9$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x-3 ga 4x+2 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$4x^{2}-10x-6=4x^{2}+3$$

Ikkala tarafdan 4x^{2} ni ayirish.

$$4x^{2}-10x-6-4x^{2}=3$$

0 ni olish uchun 4x^{2} va -4x^{2} ni birlashtirish.

$$-10x-6=3$$

6 ni ikki tarafga qo’shing.

$$-10x=3+6$$

9 olish uchun 3 va 6'ni qo'shing.

$$-10x=9$$

Ikki tarafini -10 ga bo‘ling.

$$x=\frac{9}{-10}$$

\frac{9}{-10} kasri manfiy belgini olib tashlash bilan -\frac{9}{10} sifatida qayta yozilishi mumkin.

$$x=-\frac{9}{10}$$