(x-1)(x+2)=2-(1-x) eching

$$( x - 1 ) ( x + 2 ) = 2 - ( 1 - x )$$

x uchun yechish

$$x=\sqrt{3}\approx 1,732050808$$

$$x=-\sqrt{3}\approx -1,732050808$$

Kvadrat ildizini topish bo'yicha qadamlar

x-1 ga x+2 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+x-2=2-\left(1-x\right)$$

1-x teskarisini topish uchun har birining teskarisini toping.

$$x^{2}+x-2=2-1+x$$

1 olish uchun 2 dan 1 ni ayirish.

$$x^{2}+x-2=1+x$$

Ikkala tarafdan x ni ayirish.

$$x^{2}+x-2-x=1$$

0 ni olish uchun x va -x ni birlashtirish.

$$x^{2}-2=1$$

2 ni ikki tarafga qo’shing.

$$x^{2}=1+2$$

3 olish uchun 1 va 2'ni qo'shing.

$$x^{2}=3$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{3} x=-\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

x-1 ga x+2 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+x-2=2-\left(1-x\right)$$

1-x teskarisini topish uchun har birining teskarisini toping.

$$x^{2}+x-2=2-1+x$$

1 olish uchun 2 dan 1 ni ayirish.

$$x^{2}+x-2=1+x$$

Ikkala tarafdan 1 ni ayirish.

$$x^{2}+x-2-1=x$$

-3 olish uchun -2 dan 1 ni ayirish.

$$x^{2}+x-3=x$$

Ikkala tarafdan x ni ayirish.

$$x^{2}+x-3-x=0$$

0 ni olish uchun x va -x ni birlashtirish.

$$x^{2}-3=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -3 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-3\right)}}{2}$$

-4 ni -3 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{12}}{2}$$

12 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{3}}{2}$$

x=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{3}$$

x=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{3}$$

Tenglama yechildi.

$$x=\sqrt{3} x=-\sqrt{3}$$