(x)+(x+1)+(x+3)= eching

$$( x ) + ( x + 1 ) + ( x + 3 ) =$$

Baholash

$$3x+4$$

Yechim qadamlari

2x ni olish uchun x va x ni birlashtirish.

$$2x+1+x+3$$

3x ni olish uchun 2x va x ni birlashtirish.

$$3x+1+3$$

4 olish uchun 1 va 3'ni qo'shing.

$$3x+4$$

x ga nisbatan hosilani topish

$$3$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

2x ni olish uchun x va x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x+1+x+3)$$

3x ni olish uchun 2x va x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+1+3)$$

4 olish uchun 1 va 3'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+4)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$3x^{1-1}$$

1 dan 1 ni ayirish.

$$3x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$3\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$3$$