(x^2-3)*(x+1)-(x^2+5)*(x-2)= eching

$$( x ^ { 2 } - 3 ) \cdot ( x + 1 ) - ( x ^ { 2 } + 5 ) \cdot ( x - 2 ) =$$

Baholash

$$3x^{2}-8x+7$$

Yechim qadamlari

x^{2}-3 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+x^{2}-3x-3-\left(x^{2}+5\right)\left(x-2\right)$$

x^{2}+5 ga x-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+x^{2}-3x-3-\left(x^{3}-2x^{2}+5x-10\right)$$

x^{3}-2x^{2}+5x-10 teskarisini topish uchun har birining teskarisini toping.

$$x^{3}+x^{2}-3x-3-x^{3}+2x^{2}-5x+10$$

0 ni olish uchun x^{3} va -x^{3} ni birlashtirish.

$$x^{2}-3x-3+2x^{2}-5x+10$$

3x^{2} ni olish uchun x^{2} va 2x^{2} ni birlashtirish.

$$3x^{2}-3x-3-5x+10$$

-8x ni olish uchun -3x va -5x ni birlashtirish.

$$3x^{2}-8x-3+10$$

7 olish uchun -3 va 10'ni qo'shing.

$$3x^{2}-8x+7$$

Kengaytirish

$$3x^{2}-8x+7$$

Yechim qadamlari

x^{2}-3 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+x^{2}-3x-3-\left(x^{2}+5\right)\left(x-2\right)$$

x^{2}+5 ga x-2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x^{3}+x^{2}-3x-3-\left(x^{3}-2x^{2}+5x-10\right)$$

x^{3}-2x^{2}+5x-10 teskarisini topish uchun har birining teskarisini toping.

$$x^{3}+x^{2}-3x-3-x^{3}+2x^{2}-5x+10$$

0 ni olish uchun x^{3} va -x^{3} ni birlashtirish.

$$x^{2}-3x-3+2x^{2}-5x+10$$

3x^{2} ni olish uchun x^{2} va 2x^{2} ni birlashtirish.

$$3x^{2}-3x-3-5x+10$$

-8x ni olish uchun -3x va -5x ni birlashtirish.

$$3x^{2}-8x-3+10$$

7 olish uchun -3 va 10'ni qo'shing.

$$3x^{2}-8x+7$$