(x^2-3)^3 eching

$$( x ^ { 2 } - 3 ) ^ { 3 }$$

Kengaytirish

$$x^{6}-9x^{4}+27x^{2}-27$$

Yechim qadamlari

\left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} binom teoremasini \left(x^{2}-3\right)^{3} kengaytirilishi uchun ishlating.

$$\left(x^{2}\right)^{3}-9\left(x^{2}\right)^{2}+27x^{2}-27$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$x^{6}-9\left(x^{2}\right)^{2}+27x^{2}-27$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$x^{6}-9x^{4}+27x^{2}-27$$

Baholash

$$\left(x^{2}-3\right)^{3}$$

Yechim qadamlari

\left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} binom teoremasini \left(x^{2}-3\right)^{3} kengaytirilishi uchun ishlating.

$$\left(x^{2}\right)^{3}-9\left(x^{2}\right)^{2}+27x^{2}-27$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 3 ni ko‘paytirib, 6 ni oling.

$$x^{6}-9\left(x^{2}\right)^{2}+27x^{2}-27$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring. 2 va 2 ni ko‘paytirib, 4 ni oling.

$$x^{6}-9x^{4}+27x^{2}-27$$