(x^2+xy+1)=0 eching

$$( x ^ { 2 } + x y + 1 ) = 0$$

y uchun yechish

$$y=-x-\frac{1}{x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$xy+1=-x^{2}$$

Ikkala tarafdan 1 ni ayirish.

$$xy=-x^{2}-1$$

Ikki tarafini x ga bo‘ling.

$$\frac{xy}{x}=\frac{-x^{2}-1}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$y=\frac{-x^{2}-1}{x}$$

-x^{2}-1 ni x ga bo'lish.

$$y=-x-\frac{1}{x}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{y^{2}-4}-y}{2}$$

$$x=\frac{-\sqrt{y^{2}-4}-y}{2}$$

x uchun yechish

$$x=\frac{\sqrt{y^{2}-4}-y}{2}$$

$$x=\frac{-\sqrt{y^{2}-4}-y}{2}\text{, }|y|\geq 2$$