(x+6)^2=(x+14)(x+2) eching

$$( x + 6 ) ^ { 2 } = ( x + 14 ) ( x + 2 )$$

x uchun yechish

$$x=2$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+6\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+12x+36=\left(x+14\right)\left(x+2\right)$$

x+14 ga x+2 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+12x+36=x^{2}+16x+28$$

Ikkala tarafdan x^{2} ni ayirish.

$$x^{2}+12x+36-x^{2}=16x+28$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$12x+36=16x+28$$

Ikkala tarafdan 16x ni ayirish.

$$12x+36-16x=28$$

-4x ni olish uchun 12x va -16x ni birlashtirish.

$$-4x+36=28$$

Ikkala tarafdan 36 ni ayirish.

$$-4x=28-36$$

-8 olish uchun 28 dan 36 ni ayirish.

$$-4x=-8$$

Ikki tarafini -4 ga bo‘ling.

$$x=\frac{-8}{-4}$$

2 ni olish uchun -8 ni -4 ga bo‘ling.

$$x=2$$