(x+5)(x+5)-(x-5)^2 eching

$$( x + 5 ) ( x + 5 ) - ( x - 5 ) ^ { 2 }$$

Baholash

$$20x$$

Yechim qadamlari

\left(x+5\right)^{2} hosil qilish uchun x+5 va x+5 ni ko'paytirish.

$$\left(x+5\right)^{2}-\left(x-5\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+5\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+10x+25-\left(x-5\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-5\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+10x+25-\left(x^{2}-10x+25\right)$$

x^{2}-10x+25 teskarisini topish uchun har birining teskarisini toping.

$$x^{2}+10x+25-x^{2}+10x-25$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$10x+25+10x-25$$

20x ni olish uchun 10x va 10x ni birlashtirish.

$$20x+25-25$$

0 olish uchun 25 dan 25 ni ayirish.

$$20x$$

Kengaytirish

$$20x$$

Yechim qadamlari

\left(x+5\right)^{2} hosil qilish uchun x+5 va x+5 ni ko'paytirish.

$$\left(x+5\right)^{2}-\left(x-5\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+5\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+10x+25-\left(x-5\right)^{2}$$

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-5\right)^{2} kengaytirilishi uchun ishlating.

$$x^{2}+10x+25-\left(x^{2}-10x+25\right)$$

x^{2}-10x+25 teskarisini topish uchun har birining teskarisini toping.

$$x^{2}+10x+25-x^{2}+10x-25$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$10x+25+10x-25$$

20x ni olish uchun 10x va 10x ni birlashtirish.

$$20x+25-25$$

0 olish uchun 25 dan 25 ni ayirish.

$$20x$$