(x+3)(x+1)=2x+7 eching

$$( x + 3 ) ( x + 1 ) = 2 x + 7$$

x uchun yechish (complex solution)

$$x=\sqrt{5}-1\approx 1,236067977$$

$$x=-\left(\sqrt{5}+1\right)\approx -3,236067977$$

Kvadrat tenglamalaridan foydalanish qoidalari

x+3 ga x+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+4x+3=2x+7$$

Ikkala tarafdan 2x ni ayirish.

$$x^{2}+4x+3-2x=7$$

2x ni olish uchun 4x va -2x ni birlashtirish.

$$x^{2}+2x+3=7$$

Ikkala tarafdan 7 ni ayirish.

$$x^{2}+2x+3-7=0$$

-4 olish uchun 3 dan 7 ni ayirish.

$$x^{2}+2x-4=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 2 ni b va -4 ni c bilan almashtiring.

$$x=\frac{-2±\sqrt{2^{2}-4\left(-4\right)}}{2}$$

2 kvadratini chiqarish.

$$x=\frac{-2±\sqrt{4-4\left(-4\right)}}{2}$$

-4 ni -4 marotabaga ko'paytirish.

$$x=\frac{-2±\sqrt{4+16}}{2}$$

4 ni 16 ga qo'shish.

$$x=\frac{-2±\sqrt{20}}{2}$$

20 ning kvadrat ildizini chiqarish.

$$x=\frac{-2±2\sqrt{5}}{2}$$

x=\frac{-2±2\sqrt{5}}{2} tenglamasini yeching, bunda ± musbat. -2 ni 2\sqrt{5} ga qo'shish.

$$x=\frac{2\sqrt{5}-2}{2}$$

-2+2\sqrt{5} ni 2 ga bo'lish.

$$x=\sqrt{5}-1$$

x=\frac{-2±2\sqrt{5}}{2} tenglamasini yeching, bunda ± manfiy. -2 dan 2\sqrt{5} ni ayirish.

$$x=\frac{-2\sqrt{5}-2}{2}$$

-2-2\sqrt{5} ni 2 ga bo'lish.

$$x=-\sqrt{5}-1$$

Tenglama yechildi.

$$x=\sqrt{5}-1 x=-\sqrt{5}-1$$

Kvadratni yakunlash bo'yicha qadamlar

x+3 ga x+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+4x+3=2x+7$$

Ikkala tarafdan 2x ni ayirish.

$$x^{2}+4x+3-2x=7$$

2x ni olish uchun 4x va -2x ni birlashtirish.

$$x^{2}+2x+3=7$$

Ikkala tarafdan 3 ni ayirish.

$$x^{2}+2x=7-3$$

4 olish uchun 7 dan 3 ni ayirish.

$$x^{2}+2x=4$$

2 ni bo‘lish, x shartining koeffitsienti, 2 ga 1 olish uchun. Keyin, 1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}+2x+1^{2}=4+1^{2}$$

1 kvadratini chiqarish.

$$x^{2}+2x+1=4+1$$

4 ni 1 ga qo'shish.

$$x^{2}+2x+1=5$$

x^{2}+2x+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x+1\right)^{2}=5$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x+1\right)^{2}}=\sqrt{5}$$

Qisqartirish.

$$x+1=\sqrt{5} x+1=-\sqrt{5}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$x=\sqrt{5}-1 x=-\sqrt{5}-1$$

x uchun yechish

$$x=\sqrt{5}-1\approx 1,236067977$$

$$x=-\sqrt{5}-1\approx -3,236067977$$

Kvadrat tenglamalaridan foydalanish qoidalari

x+3 ga x+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+4x+3=2x+7$$

Ikkala tarafdan 2x ni ayirish.

$$x^{2}+4x+3-2x=7$$

2x ni olish uchun 4x va -2x ni birlashtirish.

$$x^{2}+2x+3=7$$

Ikkala tarafdan 7 ni ayirish.

$$x^{2}+2x+3-7=0$$

-4 olish uchun 3 dan 7 ni ayirish.

$$x^{2}+2x-4=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 2 ni b va -4 ni c bilan almashtiring.

$$x=\frac{-2±\sqrt{2^{2}-4\left(-4\right)}}{2}$$

2 kvadratini chiqarish.

$$x=\frac{-2±\sqrt{4-4\left(-4\right)}}{2}$$

-4 ni -4 marotabaga ko'paytirish.

$$x=\frac{-2±\sqrt{4+16}}{2}$$

4 ni 16 ga qo'shish.

$$x=\frac{-2±\sqrt{20}}{2}$$

20 ning kvadrat ildizini chiqarish.

$$x=\frac{-2±2\sqrt{5}}{2}$$

x=\frac{-2±2\sqrt{5}}{2} tenglamasini yeching, bunda ± musbat. -2 ni 2\sqrt{5} ga qo'shish.

$$x=\frac{2\sqrt{5}-2}{2}$$

-2+2\sqrt{5} ni 2 ga bo'lish.

$$x=\sqrt{5}-1$$

x=\frac{-2±2\sqrt{5}}{2} tenglamasini yeching, bunda ± manfiy. -2 dan 2\sqrt{5} ni ayirish.

$$x=\frac{-2\sqrt{5}-2}{2}$$

-2-2\sqrt{5} ni 2 ga bo'lish.

$$x=-\sqrt{5}-1$$

Tenglama yechildi.

$$x=\sqrt{5}-1 x=-\sqrt{5}-1$$

Kvadratni yakunlash bo'yicha qadamlar

x+3 ga x+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+4x+3=2x+7$$

Ikkala tarafdan 2x ni ayirish.

$$x^{2}+4x+3-2x=7$$

2x ni olish uchun 4x va -2x ni birlashtirish.

$$x^{2}+2x+3=7$$

Ikkala tarafdan 3 ni ayirish.

$$x^{2}+2x=7-3$$

4 olish uchun 7 dan 3 ni ayirish.

$$x^{2}+2x=4$$

2 ni bo‘lish, x shartining koeffitsienti, 2 ga 1 olish uchun. Keyin, 1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}+2x+1^{2}=4+1^{2}$$

1 kvadratini chiqarish.

$$x^{2}+2x+1=4+1$$

4 ni 1 ga qo'shish.

$$x^{2}+2x+1=5$$

x^{2}+2x+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x+1\right)^{2}=5$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x+1\right)^{2}}=\sqrt{5}$$

Qisqartirish.

$$x+1=\sqrt{5} x+1=-\sqrt{5}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$x=\sqrt{5}-1 x=-\sqrt{5}-1$$