(x+3)(2x-3)-6x=(x-4)(2x+4)+12 eching

$$( x + 3 ) ( 2 x - 3 ) - 6 x = ( x - 4 ) ( 2 x + 4 ) + 12$$

x uchun yechish

$$x=5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x+3 ga 2x-3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}+3x-9-6x=\left(x-4\right)\left(2x+4\right)+12$$

-3x ni olish uchun 3x va -6x ni birlashtirish.

$$2x^{2}-3x-9=\left(x-4\right)\left(2x+4\right)+12$$

x-4 ga 2x+4 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2x^{2}-3x-9=2x^{2}-4x-16+12$$

-4 olish uchun -16 va 12'ni qo'shing.

$$2x^{2}-3x-9=2x^{2}-4x-4$$

Ikkala tarafdan 2x^{2} ni ayirish.

$$2x^{2}-3x-9-2x^{2}=-4x-4$$

0 ni olish uchun 2x^{2} va -2x^{2} ni birlashtirish.

$$-3x-9=-4x-4$$

4x ni ikki tarafga qo’shing.

$$-3x-9+4x=-4$$

x ni olish uchun -3x va 4x ni birlashtirish.

$$x-9=-4$$

9 ni ikki tarafga qo’shing.

$$x=-4+9$$

5 olish uchun -4 va 9'ni qo'shing.

$$x=5$$