(x+2)(x+1)=(x+4)(x+5) eching

$$( x + 2 ) ( x + 1 ) = ( x + 4 ) ( x + 5 )$$

x uchun yechish

$$x=-3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x+2 ga x+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+3x+2=\left(x+4\right)\left(x+5\right)$$

x+4 ga x+5 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$x^{2}+3x+2=x^{2}+9x+20$$

Ikkala tarafdan x^{2} ni ayirish.

$$x^{2}+3x+2-x^{2}=9x+20$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$3x+2=9x+20$$

Ikkala tarafdan 9x ni ayirish.

$$3x+2-9x=20$$

-6x ni olish uchun 3x va -9x ni birlashtirish.

$$-6x+2=20$$

Ikkala tarafdan 2 ni ayirish.

$$-6x=20-2$$

18 olish uchun 20 dan 2 ni ayirish.

$$-6x=18$$

Ikki tarafini -6 ga bo‘ling.

$$x=\frac{18}{-6}$$

-3 ni olish uchun 18 ni -6 ga bo‘ling.

$$x=-3$$