(x+1)*e^-05x eching

$$( x + 1 ) \cdot e ^ { - 05 x }$$

Baholash

$$x+1$$

Yechim qadamlari

0 hosil qilish uchun 0 va 5 ni ko'paytirish.

$$\left(x+1\right)e^{0x}$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$\left(x+1\right)e^{0}$$

0 daraja ko‘rsatkichini e ga hisoblang va 1 ni qiymatni oling.

$$\left(x+1\right)\times 1$$

x+1 ga 1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+1$$

x ga nisbatan hosilani topish

$$1$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

0 hosil qilish uchun 0 va 5 ni ko'paytirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x+1\right)e^{0x})$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x+1\right)e^{0})$$

0 daraja ko‘rsatkichini e ga hisoblang va 1 ni qiymatni oling.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(x+1\right)\times 1)$$

x+1 ga 1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+1)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$x^{1-1}$$

1 dan 1 ni ayirish.

$$x^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$1$$