(x+1/5)^2=7/25 eching

$$( x + \frac { 1 } { 5 } ) ^ { 2 } = \frac { 7 } { 25 }$$

x uchun yechish

$$x=\frac{\sqrt{7}-1}{5}\approx 0,329150262$$

$$x=\frac{-\sqrt{7}-1}{5}\approx -0,729150262$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x+\frac{1}{5}=\frac{\sqrt{7}}{5} x+\frac{1}{5}=-\frac{\sqrt{7}}{5}$$

Tenglamaning ikkala tarafidan \frac{1}{5} ni ayirish.

$$x+\frac{1}{5}-\frac{1}{5}=\frac{\sqrt{7}}{5}-\frac{1}{5} x+\frac{1}{5}-\frac{1}{5}=-\frac{\sqrt{7}}{5}-\frac{1}{5}$$

O‘zidan \frac{1}{5} ayirilsa 0 qoladi.

$$x=\frac{\sqrt{7}}{5}-\frac{1}{5} x=-\frac{\sqrt{7}}{5}-\frac{1}{5}$$

\frac{\sqrt{7}}{5} dan \frac{1}{5} ni ayirish.

$$x=\frac{\sqrt{7}-1}{5}$$

-\frac{\sqrt{7}}{5} dan \frac{1}{5} ni ayirish.

$$x=\frac{-\sqrt{7}-1}{5}$$

Tenglama yechildi.

$$x=\frac{\sqrt{7}-1}{5} x=\frac{-\sqrt{7}-1}{5}$$