(x+1/3)(x-1/4) eching

$$( x + \frac { 1 } { 3 } ) ( x - \frac { 1 } { 4 } )$$

Baholash

$$x^{2}+\frac{x}{12}-\frac{1}{12}$$

Yechim qadamlari

x+\frac{1}{3} ifodaning har bir elementini x-\frac{1}{4} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$x^{2}+x\left(-\frac{1}{4}\right)+\frac{1}{3}x+\frac{1}{3}\left(-\frac{1}{4}\right)$$

\frac{1}{12}x ni olish uchun x\left(-\frac{1}{4}\right) va \frac{1}{3}x ni birlashtirish.

$$x^{2}+\frac{1}{12}x+\frac{1}{3}\left(-\frac{1}{4}\right)$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{1}{3} ni -\frac{1}{4} ga ko‘paytiring.

$$x^{2}+\frac{1}{12}x+\frac{1\left(-1\right)}{3\times 4}$$

\frac{1\left(-1\right)}{3\times 4} kasridagi ko‘paytirishlarni bajaring.

$$x^{2}+\frac{1}{12}x+\frac{-1}{12}$$

\frac{-1}{12} kasri manfiy belgini olib tashlash bilan -\frac{1}{12} sifatida qayta yozilishi mumkin.

$$x^{2}+\frac{1}{12}x-\frac{1}{12}$$

Kengaytirish

$$x^{2}+\frac{x}{12}-\frac{1}{12}$$

Yechim qadamlari

x+\frac{1}{3} ifodaning har bir elementini x-\frac{1}{4} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$x^{2}+x\left(-\frac{1}{4}\right)+\frac{1}{3}x+\frac{1}{3}\left(-\frac{1}{4}\right)$$

\frac{1}{12}x ni olish uchun x\left(-\frac{1}{4}\right) va \frac{1}{3}x ni birlashtirish.

$$x^{2}+\frac{1}{12}x+\frac{1}{3}\left(-\frac{1}{4}\right)$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{1}{3} ni -\frac{1}{4} ga ko‘paytiring.

$$x^{2}+\frac{1}{12}x+\frac{1\left(-1\right)}{3\times 4}$$

\frac{1\left(-1\right)}{3\times 4} kasridagi ko‘paytirishlarni bajaring.

$$x^{2}+\frac{1}{12}x+\frac{-1}{12}$$

\frac{-1}{12} kasri manfiy belgini olib tashlash bilan -\frac{1}{12} sifatida qayta yozilishi mumkin.

$$x^{2}+\frac{1}{12}x-\frac{1}{12}$$