(q^4)^2 eching

$$( q ^ { 4 } ) ^ { 2 }$$

Baholash

$$q^{8}$$

Oshib boruvchi tartibdan boshqa tartib uchun qadamlar

Ifodani qisqartirish uchun eksponent qoidalaridan foydalanish.

$$\left(q^{4}\right)^{2}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring.

$$q^{4\times 2}$$

4 ni 2 marotabaga ko'paytirish.

$$q^{8}$$

q ga nisbatan hosilani topish

$$8q^{7}$$

Zanjirli qoidadan foydalanish qadamalari

Agar F ikki differensial funksiya f\left(u\right) va u=g\left(x\right)'ning yig'indisi bo'lsa, ya'ni agar F\left(x\right)=f\left(g\left(x\right)\right) bo'lsa, F hosilasi f'ning u martalik hosilasi, g'ning x martalik hosilasi ya'ni \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right) bo'ladi.

$$2\left(q^{4}\right)^{2-1}\frac{\mathrm{d}}{\mathrm{d}q}(q^{4})$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2\left(q^{4}\right)^{1}\times 4q^{4-1}$$

Qisqartirish.

$$8q^{3}\left(q^{4}\right)^{1}$$

Har qanday t sharti uchun t^{1}=t.

$$8q^{3}q^{4}$$