(n-2sqrt{2})(n+2sqrt{2}) eching

$$( n - 2 \sqrt { 2 } ) ( n + 2 \sqrt { 2 } )$$

Baholash

$$n^{2}-8$$

Yechim qadamlari

Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$n^{2}-\left(2\sqrt{2}\right)^{2}$$

\left(2\sqrt{2}\right)^{2} ni kengaytirish.

$$n^{2}-2^{2}\left(\sqrt{2}\right)^{2}$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$n^{2}-4\left(\sqrt{2}\right)^{2}$$

\sqrt{2} kvadrati – 2.

$$n^{2}-4\times 2$$

8 hosil qilish uchun 4 va 2 ni ko'paytirish.

$$n^{2}-8$$

n ga nisbatan hosilani topish

$$2n$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

Hisoblang: \left(n-2\sqrt{2}\right)\left(n+2\sqrt{2}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n^{2}-\left(2\sqrt{2}\right)^{2})$$

\left(2\sqrt{2}\right)^{2} ni kengaytirish.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n^{2}-2^{2}\left(\sqrt{2}\right)^{2})$$

2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n^{2}-4\left(\sqrt{2}\right)^{2})$$

\sqrt{2} kvadrati – 2.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n^{2}-4\times 2)$$

8 hosil qilish uchun 4 va 2 ni ko'paytirish.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n^{2}-8)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2n^{2-1}$$

2 dan 1 ni ayirish.

$$2n^{1}$$

Har qanday t sharti uchun t^{1}=t.

$$2n$$