(m)(r-1)(r+3)=5(r+3) eching

$$( m ) ( r - 1 ) ( r + 3 ) = 5 ( r + 3 )$$

m uchun yechish

$$\left\{\begin{matrix}m=\frac{5}{r-1}\text{, }&r\neq 1\\m\in \mathrm{R}\text{, }&r=-3\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

m ga r-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(mr-m\right)\left(r+3\right)=5\left(r+3\right)$$

mr-m ga r+3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$mr^{2}+2mr-3m=5\left(r+3\right)$$

5 ga r+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$mr^{2}+2mr-3m=5r+15$$

m'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(r^{2}+2r-3\right)m=5r+15$$

Ikki tarafini r^{2}+2r-3 ga bo‘ling.

$$\frac{\left(r^{2}+2r-3\right)m}{r^{2}+2r-3}=\frac{5r+15}{r^{2}+2r-3}$$

r^{2}+2r-3 ga bo'lish r^{2}+2r-3 ga ko'paytirishni bekor qiladi.

$$m=\frac{5r+15}{r^{2}+2r-3}$$

15+5r ni r^{2}+2r-3 ga bo'lish.

$$m=\frac{5}{r-1}$$

r uchun yechish

$$\left\{\begin{matrix}\\r=-3\text{, }&\text{unconditionally}\\r=\frac{m+5}{m}\text{, }&m\neq 0\end{matrix}\right,$$