Asosiy tarkibga oʻtish
m uchun yechish
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γ_μ uchun yechish
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Veb-qidiruvdagi o'xshash muammolar

Baham ko'rish

i\gamma _{μ}∂^{\mu }\psi -m\psi =0
i\gamma _{μ}∂^{\mu }-m ga \psi ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
-m\psi =-i\gamma _{μ}∂^{\mu }\psi
Ikkala tarafdan i\gamma _{μ}∂^{\mu }\psi ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.
\left(-\psi \right)m=-i\gamma _{μ}\psi ∂^{\mu }
Tenglama standart shaklda.
\frac{\left(-\psi \right)m}{-\psi }=-\frac{i\gamma _{μ}\psi ∂^{\mu }}{-\psi }
Ikki tarafini -\psi ga bo‘ling.
m=-\frac{i\gamma _{μ}\psi ∂^{\mu }}{-\psi }
-\psi ga bo'lish -\psi ga ko'paytirishni bekor qiladi.
m=i\gamma _{μ}∂^{\mu }
-i\gamma _{μ}∂^{\mu }\psi ni -\psi ga bo'lish.
i\gamma _{μ}∂^{\mu }\psi -m\psi =0
i\gamma _{μ}∂^{\mu }-m ga \psi ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
i\gamma _{μ}∂^{\mu }\psi =m\psi
m\psi ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.
i\psi ∂^{\mu }\gamma _{μ}=m\psi
Tenglama standart shaklda.
\frac{i\psi ∂^{\mu }\gamma _{μ}}{i\psi ∂^{\mu }}=\frac{m\psi }{i\psi ∂^{\mu }}
Ikki tarafini i∂^{\mu }\psi ga bo‘ling.
\gamma _{μ}=\frac{m\psi }{i\psi ∂^{\mu }}
i∂^{\mu }\psi ga bo'lish i∂^{\mu }\psi ga ko'paytirishni bekor qiladi.
\gamma _{μ}=-\frac{im}{∂^{\mu }}
m\psi ni i∂^{\mu }\psi ga bo'lish.