(a+ib-5)(a-ib-5 eching

$$( a + i b - 5 ) ( a - i b - 5$$

Baholash

$$\left(a-5\right)^{2}+b^{2}$$

Yechim qadamlari

a+ib-5 ifodaning har bir elementini a-ib-5 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$a\left(a-ib\right)-5a+ib\left(a-ib\right)-5ib-5\left(a-ib\right)+25$$

a ga a-ib ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-iab-5a+ib\left(a-ib\right)-5ib-5\left(a-ib\right)+25$$

ib ga a-ib ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-iab-5a+iba+b^{2}-5ib-5\left(a-ib\right)+25$$

0 ni olish uchun -iab va iba ni birlashtirish.

$$a^{2}-5a+b^{2}-5ib-5\left(a-ib\right)+25$$

-5 ga a-ib ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-5a+b^{2}-5ib-5a+5ib+25$$

-10a ni olish uchun -5a va -5a ni birlashtirish.

$$a^{2}-10a+b^{2}-5ib+5ib+25$$

0 ni olish uchun -5ib va 5ib ni birlashtirish.

$$a^{2}-10a+b^{2}+25$$

Kengaytirish

$$a^{2}-10a+b^{2}+25$$

Yechim qadamlari

a+ib-5 ifodaning har bir elementini a-ib-5 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$a\left(a-ib\right)-5a+ib\left(a-ib\right)-5ib-5\left(a-ib\right)+25$$

a ga a-ib ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-iab-5a+ib\left(a-ib\right)-5ib-5\left(a-ib\right)+25$$

ib ga a-ib ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-iab-5a+iba+b^{2}-5ib-5\left(a-ib\right)+25$$

0 ni olish uchun -iab va iba ni birlashtirish.

$$a^{2}-5a+b^{2}-5ib-5\left(a-ib\right)+25$$

-5 ga a-ib ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}-5a+b^{2}-5ib-5a+5ib+25$$

-10a ni olish uchun -5a va -5a ni birlashtirish.

$$a^{2}-10a+b^{2}-5ib+5ib+25$$

0 ni olish uchun -5ib va 5ib ni birlashtirish.

$$a^{2}-10a+b^{2}+25$$