a uchun yechish (complex solution)
\left\{\begin{matrix}a=-\frac{bx-x-b-5}{x+1}\text{, }&x\neq -1\\a\in \mathrm{C}\text{, }&x=-1\text{ and }b=-2\end{matrix}\right,
b uchun yechish (complex solution)
\left\{\begin{matrix}b=-\frac{ax-x+a-5}{x-1}\text{, }&x\neq 1\\b\in \mathrm{C}\text{, }&x=1\text{ and }a=3\end{matrix}\right,
a uchun yechish
\left\{\begin{matrix}a=-\frac{bx-x-b-5}{x+1}\text{, }&x\neq -1\\a\in \mathrm{R}\text{, }&x=-1\text{ and }b=-2\end{matrix}\right,
b uchun yechish
\left\{\begin{matrix}b=-\frac{ax-x+a-5}{x-1}\text{, }&x\neq 1\\b\in \mathrm{R}\text{, }&x=1\text{ and }a=3\end{matrix}\right,
Grafik
Baham ko'rish
Klipbordga nusxa olish
ax+bx+a-b+1=x+6
a+b ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
ax+a-b+1=x+6-bx
Ikkala tarafdan bx ni ayirish.
ax+a+1=x+6-bx+b
b ni ikki tarafga qo’shing.
ax+a=x+6-bx+b-1
Ikkala tarafdan 1 ni ayirish.
ax+a=x+5-bx+b
5 olish uchun 6 dan 1 ni ayirish.
\left(x+1\right)a=x+5-bx+b
a'ga ega bo'lgan barcha shartlarni birlashtirish.
\left(x+1\right)a=5+b+x-bx
Tenglama standart shaklda.
\frac{\left(x+1\right)a}{x+1}=\frac{5+b+x-bx}{x+1}
Ikki tarafini x+1 ga bo‘ling.
a=\frac{5+b+x-bx}{x+1}
x+1 ga bo'lish x+1 ga ko'paytirishni bekor qiladi.
ax+bx+a-b+1=x+6
a+b ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
bx+a-b+1=x+6-ax
Ikkala tarafdan ax ni ayirish.
bx-b+1=x+6-ax-a
Ikkala tarafdan a ni ayirish.
bx-b=x+6-ax-a-1
Ikkala tarafdan 1 ni ayirish.
bx-b=x+5-ax-a
5 olish uchun 6 dan 1 ni ayirish.
\left(x-1\right)b=x+5-ax-a
b'ga ega bo'lgan barcha shartlarni birlashtirish.
\left(x-1\right)b=5-a+x-ax
Tenglama standart shaklda.
\frac{\left(x-1\right)b}{x-1}=\frac{5-a+x-ax}{x-1}
Ikki tarafini x-1 ga bo‘ling.
b=\frac{5-a+x-ax}{x-1}
x-1 ga bo'lish x-1 ga ko'paytirishni bekor qiladi.
ax+bx+a-b+1=x+6
a+b ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
ax+a-b+1=x+6-bx
Ikkala tarafdan bx ni ayirish.
ax+a+1=x+6-bx+b
b ni ikki tarafga qo’shing.
ax+a=x+6-bx+b-1
Ikkala tarafdan 1 ni ayirish.
ax+a=x+5-bx+b
5 olish uchun 6 dan 1 ni ayirish.
\left(x+1\right)a=x+5-bx+b
a'ga ega bo'lgan barcha shartlarni birlashtirish.
\left(x+1\right)a=5+b+x-bx
Tenglama standart shaklda.
\frac{\left(x+1\right)a}{x+1}=\frac{5+b+x-bx}{x+1}
Ikki tarafini x+1 ga bo‘ling.
a=\frac{5+b+x-bx}{x+1}
x+1 ga bo'lish x+1 ga ko'paytirishni bekor qiladi.
ax+bx+a-b+1=x+6
a+b ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
bx+a-b+1=x+6-ax
Ikkala tarafdan ax ni ayirish.
bx-b+1=x+6-ax-a
Ikkala tarafdan a ni ayirish.
bx-b=x+6-ax-a-1
Ikkala tarafdan 1 ni ayirish.
bx-b=x+5-ax-a
5 olish uchun 6 dan 1 ni ayirish.
\left(x-1\right)b=x+5-ax-a
b'ga ega bo'lgan barcha shartlarni birlashtirish.
\left(x-1\right)b=5-a+x-ax
Tenglama standart shaklda.
\frac{\left(x-1\right)b}{x-1}=\frac{5-a+x-ax}{x-1}
Ikki tarafini x-1 ga bo‘ling.
b=\frac{5-a+x-ax}{x-1}
x-1 ga bo'lish x-1 ga ko'paytirishni bekor qiladi.
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