(a+b+c)-(a-b-c)*(2a+b)-(b+c)*(a+b) eching

$$( a + b + c ) - ( a - b - c ) \cdot ( 2 a + b ) - ( b + c ) \cdot ( a + b )$$

Baholash

$$c+b+a+ac-2a^{2}$$

Yechim qadamlari

a-b-c ifodaning har bir elementini 2a+b ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$a+b+c-\left(2a^{2}+ab-2ba-b^{2}-2ca-cb\right)-\left(b+c\right)\left(a+b\right)$$

-ab ni olish uchun ab va -2ba ni birlashtirish.

$$a+b+c-\left(2a^{2}-ab-b^{2}-2ca-cb\right)-\left(b+c\right)\left(a+b\right)$$

2a^{2}-ab-b^{2}-2ca-cb teskarisini topish uchun har birining teskarisini toping.

$$a+b+c-2a^{2}-\left(-ab\right)-\left(-b^{2}\right)-\left(-2ca\right)-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-ab ning teskarisi ab ga teng.

$$a+b+c-2a^{2}+ab-\left(-b^{2}\right)-\left(-2ca\right)-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-b^{2} ning teskarisi b^{2} ga teng.

$$a+b+c-2a^{2}+ab+b^{2}-\left(-2ca\right)-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-2ca ning teskarisi 2ca ga teng.

$$a+b+c-2a^{2}+ab+b^{2}+2ca-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-cb ning teskarisi cb ga teng.

$$a+b+c-2a^{2}+ab+b^{2}+2ca+cb-\left(b+c\right)\left(a+b\right)$$

b+c ifodaning har bir elementini a+b ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$a+b+c-2a^{2}+ab+b^{2}+2ca+cb-\left(ba+b^{2}+ca+cb\right)$$

ba+b^{2}+ca+cb teskarisini topish uchun har birining teskarisini toping.

$$a+b+c-2a^{2}+ab+b^{2}+2ca+cb-ba-b^{2}-ca-cb$$

0 ni olish uchun ab va -ba ni birlashtirish.

$$a+b+c-2a^{2}+b^{2}+2ca+cb-b^{2}-ca-cb$$

0 ni olish uchun b^{2} va -b^{2} ni birlashtirish.

$$a+b+c-2a^{2}+2ca+cb-ca-cb$$

ca ni olish uchun 2ca va -ca ni birlashtirish.

$$a+b+c-2a^{2}+ca+cb-cb$$

0 ni olish uchun cb va -cb ni birlashtirish.

$$a+b+c-2a^{2}+ca$$

Kengaytirish

$$c+b+a+ac-2a^{2}$$

Yechim qadamlari

a-b-c ifodaning har bir elementini 2a+b ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$a+b+c-\left(2a^{2}+ab-2ba-b^{2}-2ca-cb\right)-\left(b+c\right)\left(a+b\right)$$

-ab ni olish uchun ab va -2ba ni birlashtirish.

$$a+b+c-\left(2a^{2}-ab-b^{2}-2ca-cb\right)-\left(b+c\right)\left(a+b\right)$$

2a^{2}-ab-b^{2}-2ca-cb teskarisini topish uchun har birining teskarisini toping.

$$a+b+c-2a^{2}-\left(-ab\right)-\left(-b^{2}\right)-\left(-2ca\right)-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-ab ning teskarisi ab ga teng.

$$a+b+c-2a^{2}+ab-\left(-b^{2}\right)-\left(-2ca\right)-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-b^{2} ning teskarisi b^{2} ga teng.

$$a+b+c-2a^{2}+ab+b^{2}-\left(-2ca\right)-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-2ca ning teskarisi 2ca ga teng.

$$a+b+c-2a^{2}+ab+b^{2}+2ca-\left(-cb\right)-\left(b+c\right)\left(a+b\right)$$

-cb ning teskarisi cb ga teng.

$$a+b+c-2a^{2}+ab+b^{2}+2ca+cb-\left(b+c\right)\left(a+b\right)$$

b+c ifodaning har bir elementini a+b ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$a+b+c-2a^{2}+ab+b^{2}+2ca+cb-\left(ba+b^{2}+ca+cb\right)$$

ba+b^{2}+ca+cb teskarisini topish uchun har birining teskarisini toping.

$$a+b+c-2a^{2}+ab+b^{2}+2ca+cb-ba-b^{2}-ca-cb$$

0 ni olish uchun ab va -ba ni birlashtirish.

$$a+b+c-2a^{2}+b^{2}+2ca+cb-b^{2}-ca-cb$$

0 ni olish uchun b^{2} va -b^{2} ni birlashtirish.

$$a+b+c-2a^{2}+2ca+cb-ca-cb$$

ca ni olish uchun 2ca va -ca ni birlashtirish.

$$a+b+c-2a^{2}+ca+cb-cb$$

0 ni olish uchun cb va -cb ni birlashtirish.

$$a+b+c-2a^{2}+ca$$