(a+2)^2-5(3-2a)+(2a-3)^2 eching

$$( a + 2 ) ^ { 2 } - 5 ( 3 - 2 a ) + ( 2 a - 3 ) ^ { 2 }$$

Baholash

$$5a^{2}+2a-2$$

Yechim qadamlari

\left(p+q\right)^{2}=p^{2}+2pq+q^{2} binom teoremasini \left(a+2\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}+4a+4-5\left(3-2a\right)+\left(2a-3\right)^{2}$$

-5 ga 3-2a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}+4a+4-15+10a+\left(2a-3\right)^{2}$$

-11 olish uchun 4 dan 15 ni ayirish.

$$a^{2}+4a-11+10a+\left(2a-3\right)^{2}$$

14a ni olish uchun 4a va 10a ni birlashtirish.

$$a^{2}+14a-11+\left(2a-3\right)^{2}$$

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(2a-3\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}+14a-11+4a^{2}-12a+9$$

5a^{2} ni olish uchun a^{2} va 4a^{2} ni birlashtirish.

$$5a^{2}+14a-11-12a+9$$

2a ni olish uchun 14a va -12a ni birlashtirish.

$$5a^{2}+2a-11+9$$

-2 olish uchun -11 va 9'ni qo'shing.

$$5a^{2}+2a-2$$

Kengaytirish

$$5a^{2}+2a-2$$

Yechim qadamlari

\left(p+q\right)^{2}=p^{2}+2pq+q^{2} binom teoremasini \left(a+2\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}+4a+4-5\left(3-2a\right)+\left(2a-3\right)^{2}$$

-5 ga 3-2a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$a^{2}+4a+4-15+10a+\left(2a-3\right)^{2}$$

-11 olish uchun 4 dan 15 ni ayirish.

$$a^{2}+4a-11+10a+\left(2a-3\right)^{2}$$

14a ni olish uchun 4a va 10a ni birlashtirish.

$$a^{2}+14a-11+\left(2a-3\right)^{2}$$

\left(p-q\right)^{2}=p^{2}-2pq+q^{2} binom teoremasini \left(2a-3\right)^{2} kengaytirilishi uchun ishlating.

$$a^{2}+14a-11+4a^{2}-12a+9$$

5a^{2} ni olish uchun a^{2} va 4a^{2} ni birlashtirish.

$$5a^{2}+14a-11-12a+9$$

2a ni olish uchun 14a va -12a ni birlashtirish.

$$5a^{2}+2a-11+9$$

-2 olish uchun -11 va 9'ni qo'shing.

$$5a^{2}+2a-2$$