(8x^3)/(2x^-7) eching

$$( 8 x ^ { 3 } ) / ( 2 x ^ { - 7 } )$$

Baholash

$$4x^{10}$$

Ikki eksponentning koʻpaytmasi uchun qadamlar

Ifodani qisqartirish uchun eksponent qoidalaridan foydalanish.

$$\left(8x^{3}\right)^{1}\times \frac{1}{2x^{-7}}$$

Ikki yoki undan ko'p raqam koʻpaytmasini daraja ko'rsatkichiga oshirish uchun har bir raqamni daraja ko'rsatkichiga oshiring va ularning koʻpaytmasini chiqaring.

$$8^{1}\left(x^{3}\right)^{1}\times \frac{1}{2}\times \frac{1}{x^{-7}}$$

Ko'paytirishning kommutativ xususiyatidan foydalanish.

$$8^{1}\times \frac{1}{2}\left(x^{3}\right)^{1}\times \frac{1}{x^{-7}}$$

Daraja ko‘rsatkichini boshqa ko‘rsatkichga oshirish uchun, darajalarini ko‘paytiring.

$$8^{1}\times \frac{1}{2}x^{3}x^{-7\left(-1\right)}$$

-7 ni -1 marotabaga ko'paytirish.

$$8^{1}\times \frac{1}{2}x^{3}x^{7}$$

Ayni daraja ko'rsatkichlarini ko'paytirish uchun ularning darajalarini qo'shing.

$$8^{1}\times \frac{1}{2}x^{3+7}$$

3 va 7 belgilarini qo'shish.

$$8^{1}\times \frac{1}{2}x^{10}$$

8 ni 1 daraja ko'rsatgichiga oshirish.

$$8\times \frac{1}{2}x^{10}$$

8 ni \frac{1}{2} marotabaga ko'paytirish.

$$4x^{10}$$

x ga nisbatan hosilani topish

$$40x^{9}$$

Yechim qadamlari

Ayni asosning daraja ko'rsatkichi bo'lish uchun maxrajning darajasini surat darajasidan bo'ling.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{8}{2}x^{3-\left(-7\right)})$$

Arifmetik hisobni amalga oshirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{10})$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$10\times 4x^{10-1}$$

Arifmetik hisobni amalga oshirish.

$$40x^{9}$$