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11x^{2}-2x+1+5x-8
11x^{2} ni olish uchun 8x^{2} va 3x^{2} ni birlashtirish.
11x^{2}+3x+1-8
3x ni olish uchun -2x va 5x ni birlashtirish.
11x^{2}+3x-7
-7 olish uchun 1 dan 8 ni ayirish.
factor(11x^{2}-2x+1+5x-8)
11x^{2} ni olish uchun 8x^{2} va 3x^{2} ni birlashtirish.
factor(11x^{2}+3x+1-8)
3x ni olish uchun -2x va 5x ni birlashtirish.
factor(11x^{2}+3x-7)
-7 olish uchun 1 dan 8 ni ayirish.
11x^{2}+3x-7=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-3±\sqrt{3^{2}-4\times 11\left(-7\right)}}{2\times 11}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-3±\sqrt{9-4\times 11\left(-7\right)}}{2\times 11}
3 kvadratini chiqarish.
x=\frac{-3±\sqrt{9-44\left(-7\right)}}{2\times 11}
-4 ni 11 marotabaga ko'paytirish.
x=\frac{-3±\sqrt{9+308}}{2\times 11}
-44 ni -7 marotabaga ko'paytirish.
x=\frac{-3±\sqrt{317}}{2\times 11}
9 ni 308 ga qo'shish.
x=\frac{-3±\sqrt{317}}{22}
2 ni 11 marotabaga ko'paytirish.
x=\frac{\sqrt{317}-3}{22}
x=\frac{-3±\sqrt{317}}{22} tenglamasini yeching, bunda ± musbat. -3 ni \sqrt{317} ga qo'shish.
x=\frac{-\sqrt{317}-3}{22}
x=\frac{-3±\sqrt{317}}{22} tenglamasini yeching, bunda ± manfiy. -3 dan \sqrt{317} ni ayirish.
11x^{2}+3x-7=11\left(x-\frac{\sqrt{317}-3}{22}\right)\left(x-\frac{-\sqrt{317}-3}{22}\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-3+\sqrt{317}}{22} ga va x_{2} uchun \frac{-3-\sqrt{317}}{22} ga bo‘ling.