(8-x)^2=x^2+6^2 eching

$$( 8 - x ) ^ { 2 } = x ^ { 2 } + 6 ^ { 2 }$$

x uchun yechish

$$x = \frac{7}{4} = 1\frac{3}{4} = 1,75$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(8-x\right)^{2} kengaytirilishi uchun ishlating.

$$64-16x+x^{2}=x^{2}+6^{2}$$

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$64-16x+x^{2}=x^{2}+36$$

Ikkala tarafdan x^{2} ni ayirish.

$$64-16x+x^{2}-x^{2}=36$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$64-16x=36$$

Ikkala tarafdan 64 ni ayirish.

$$-16x=36-64$$

-28 olish uchun 36 dan 64 ni ayirish.

$$-16x=-28$$

Ikki tarafini -16 ga bo‘ling.

$$x=\frac{-28}{-16}$$

\frac{-28}{-16} ulushini -4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{7}{4}$$