(7u^2-5u+3)+(-u^2+2u+4) eching

$$( 7 u ^ { 2 } - 5 u + 3 ) + ( - u ^ { 2 } + 2 u + 4 )$$

Baholash

$$6u^{2}-3u+7$$

Yechim qadamlari

-3u ni olish uchun -5u va 2u ni birlashtirish.

$$7u^{2}-3u+3-u^{2}+4$$

7 olish uchun 3 va 4'ni qo'shing.

$$7u^{2}-3u+7-u^{2}$$

6u^{2} ni olish uchun 7u^{2} va -u^{2} ni birlashtirish.

$$6u^{2}-3u+7$$

u ga nisbatan hosilani topish

$$12u-3$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

-3u ni olish uchun -5u va 2u ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}u}(7u^{2}-3u+3-u^{2}+4)$$

7 olish uchun 3 va 4'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}u}(7u^{2}-3u+7-u^{2})$$

6u^{2} ni olish uchun 7u^{2} va -u^{2} ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}u}(6u^{2}-3u+7)$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2\times 6u^{2-1}-3u^{1-1}$$

2 ni 6 marotabaga ko'paytirish.

$$12u^{2-1}-3u^{1-1}$$

2 dan 1 ni ayirish.

$$12u^{1}-3u^{1-1}$$

1 dan 1 ni ayirish.

$$12u^{1}-3u^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$12u-3u^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$12u-3$$