(6x-5)^2=50 eching

$$( 6 x - 5 ) ^ { 2 } = 50$$

x uchun yechish

$$x = \frac{5 \sqrt{2} + 5}{6} \approx 2,011844635$$

$$x=\frac{5-5\sqrt{2}}{6}\approx -0,345177969$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$6x-5=5\sqrt{2} 6x-5=-5\sqrt{2}$$

5 ni tenglamaning ikkala tarafiga qo'shish.

$$6x-5-\left(-5\right)=5\sqrt{2}-\left(-5\right) 6x-5-\left(-5\right)=-5\sqrt{2}-\left(-5\right)$$

O‘zidan -5 ayirilsa 0 qoladi.

$$6x=5\sqrt{2}-\left(-5\right) 6x=-5\sqrt{2}-\left(-5\right)$$

5\sqrt{2} dan -5 ni ayirish.

$$6x=5\sqrt{2}+5$$

-5\sqrt{2} dan -5 ni ayirish.

$$6x=5-5\sqrt{2}$$

Ikki tarafini 6 ga bo‘ling.

$$\frac{6x}{6}=\frac{5\sqrt{2}+5}{6} \frac{6x}{6}=\frac{5-5\sqrt{2}}{6}$$

6 ga bo'lish 6 ga ko'paytirishni bekor qiladi.

$$x=\frac{5\sqrt{2}+5}{6} x=\frac{5-5\sqrt{2}}{6}$$