(6-12)^2div[sqrt{9}(1+3)]? eching

$$( 6 - 12 ) ^ { 2 } \div [ \sqrt { 9 } ( 1 + 3 ) ] ?$$

Baholash

$$3$$

Yechim qadamlari

-6 olish uchun 6 dan 12 ni ayirish.

$$\frac{\left(-6\right)^{2}}{\sqrt{9}\left(1+3\right)}$$

2 daraja ko‘rsatkichini -6 ga hisoblang va 36 ni qiymatni oling.

$$\frac{36}{\sqrt{9}\left(1+3\right)}$$

9 ning kvadrat ildizini hisoblab, 3 natijaga ega bo‘ling.

$$\frac{36}{3\left(1+3\right)}$$

4 olish uchun 1 va 3'ni qo'shing.

$$\frac{36}{3\times 4}$$

12 hosil qilish uchun 3 va 4 ni ko'paytirish.

$$\frac{36}{12}$$

3 ni olish uchun 36 ni 12 ga bo‘ling.

$$3$$

Omil

$$3$$