(5n-4/5)(5n-1/5) eching

$$( 5 n - \frac { 4 } { 5 } ) ( 5 n - \frac { 1 } { 5 } )$$

Baholash

$$25n^{2}-5n+\frac{4}{25}$$

Yechim qadamlari

5n-\frac{4}{5} ifodaning har bir elementini 5n-\frac{1}{5} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$25n^{2}+5n\left(-\frac{1}{5}\right)-\frac{4}{5}\times 5n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

5 va 5 ni qisqartiring.

$$25n^{2}-n-\frac{4}{5}\times 5n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

5 va 5 ni qisqartiring.

$$25n^{2}-n-4n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

-5n ni olish uchun -n va -4n ni birlashtirish.

$$25n^{2}-5n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali -\frac{4}{5} ni -\frac{1}{5} ga ko‘paytiring.

$$25n^{2}-5n+\frac{-4\left(-1\right)}{5\times 5}$$

\frac{-4\left(-1\right)}{5\times 5} kasridagi ko‘paytirishlarni bajaring.

$$25n^{2}-5n+\frac{4}{25}$$

Kengaytirish

$$25n^{2}-5n+\frac{4}{25}$$

Yechim qadamlari

5n-\frac{4}{5} ifodaning har bir elementini 5n-\frac{1}{5} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$25n^{2}+5n\left(-\frac{1}{5}\right)-\frac{4}{5}\times 5n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

5 va 5 ni qisqartiring.

$$25n^{2}-n-\frac{4}{5}\times 5n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

5 va 5 ni qisqartiring.

$$25n^{2}-n-4n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

-5n ni olish uchun -n va -4n ni birlashtirish.

$$25n^{2}-5n-\frac{4}{5}\left(-\frac{1}{5}\right)$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali -\frac{4}{5} ni -\frac{1}{5} ga ko‘paytiring.

$$25n^{2}-5n+\frac{-4\left(-1\right)}{5\times 5}$$

\frac{-4\left(-1\right)}{5\times 5} kasridagi ko‘paytirishlarni bajaring.

$$25n^{2}-5n+\frac{4}{25}$$